{"id":1161,"date":"2026-01-19T14:30:27","date_gmt":"2026-01-19T04:30:27","guid":{"rendered":"https:\/\/archive4ones.com\/2ndstudy\/?p=1161"},"modified":"2026-01-19T14:30:27","modified_gmt":"2026-01-19T04:30:27","slug":"year11-math-3-1-5","status":"publish","type":"post","link":"https:\/\/archive4ones.com\/2ndstudy\/?p=1161","title":{"rendered":"Year11-MATH-3-1-5"},"content":{"rendered":"\n

Chapter 5: Trigonometric Functions<\/h3>\n\n\n\n

In previous years, trigonometry was about triangles. In Mathematical Methods, we transition to Circular Functions<\/strong>. We treat sine and cosine as waves that repeat infinitely, which allows us to model periodic phenomena like tides, sound waves, and seasonal temperature shifts.<\/p>\n\n\n\n

\n\n\n\n

5.1 Radian Measure<\/h3>\n\n\n\n

Before performing calculus on trigonometric functions, we must use radians<\/strong> instead of degrees. Radians measure the arc length along a unit circle.<\/p>\n\n\n\n

    \n
  • Conversion:<\/strong> \u03c0<\/mi> radians<\/mtext>=<\/mo>180<\/mn>\u2218<\/mo><\/msup><\/mrow>\\pi \\text{ radians} = 180^\\circ<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
  • To Radians:<\/strong> Multiply by \u03c0<\/mi>180<\/mn><\/mfrac>\\frac{\\pi}{180}<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
  • To Degrees:<\/strong> Multiply by 180<\/mn>\u03c0<\/mi><\/mfrac>\\frac{180}{\\pi}<\/annotation><\/semantics><\/math><\/li>\n<\/ul>\n\n\n\n
    \n

    Note:<\/strong> Always ensure your calculator is in RAD<\/strong> mode when working with calculus in this subject.<\/p>\n<\/blockquote>\n\n\n\n

    \n\n\n\n

    5.2 The Unit Circle<\/h3>\n\n\n\n

    The unit circle is a circle with a radius of 1 centered at the origin (<\/mo>0,0<\/mn>)<\/mo><\/mrow>(0,0)<\/annotation><\/semantics><\/math>. For any point (<\/mo>x<\/mi>,<\/mo>y<\/mi>)<\/mo><\/mrow>(x,y)<\/annotation><\/semantics><\/math> on the circle at an angle \u03b8<\/mi>\\theta<\/annotation><\/semantics><\/math>:<\/p>\n\n\n\n
      \n
    • x<\/mi>=<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03b8<\/mi>)<\/mo><\/mrow>x = \\cos(\\theta)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
    • y<\/mi>=<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03b8<\/mi>)<\/mo><\/mrow>y = \\sin(\\theta)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
    • tan<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03b8<\/mi>)<\/mo>=<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03b8<\/mi>)<\/mo><\/mrow>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03b8<\/mi>)<\/mo><\/mrow><\/mfrac><\/mrow>\\tan(\\theta) = \\frac{\\sin(\\theta)}{\\cos(\\theta)}<\/annotation><\/semantics><\/math><\/li>\n<\/ul>\n\n\n\n
      \n\n\n\n

      5.3 Graphs of Sine and Cosine<\/h3>\n\n\n\n

      The standard functions y<\/mi>=<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>y = \\sin(x)<\/annotation><\/semantics><\/math> and y<\/mi>=<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>y = \\cos(x)<\/annotation><\/semantics><\/math> produce periodic waves. We often study transformed versions:<\/p>\n\n\n\n

      y<\/mi>=<\/mo>A<\/mi><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>B<\/mi>(<\/mo>x<\/mi>\u2212<\/mo>C<\/mi>)<\/mo>)<\/mo>+<\/mo>D<\/mi><\/mrow>y = A\\sin(B(x – C)) + D<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
        \n
      • A<\/mi>A<\/annotation><\/semantics><\/math> (Amplitude):<\/strong> The height of the wave from the center.<\/li>\n\n\n\n
      • B<\/mi>B<\/annotation><\/semantics><\/math> (Period Factor):<\/strong> Used to find the Period (P<\/mi>P<\/annotation><\/semantics><\/math>), which is the distance for one full cycle. P<\/mi>=<\/mo>2<\/mn>\u03c0<\/mi><\/mrow>B<\/mi><\/mfrac><\/mrow>P = \\frac{2\\pi}{B}<\/annotation><\/semantics><\/math>.<\/li>\n\n\n\n
      • C<\/mi>C<\/annotation><\/semantics><\/math> (Phase Shift):<\/strong> Horizontal translation.<\/li>\n\n\n\n
      • D<\/mi>D<\/annotation><\/semantics><\/math> (Mean Height):<\/strong> Vertical translation (the new center line).<\/li>\n<\/ul>\n\n\n\n
        \n\n\n\n

        5.4 Derivatives of Trigonometric Functions<\/h3>\n\n\n\n

        One of the most remarkable patterns in calculus is how sine and cosine relate to each other’s gradients.<\/p>\n\n\n\n

          \n
        • The Derivative of Sine:d<\/mi>d<\/mi>x<\/mi><\/mrow><\/mfrac>(<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>k<\/mi>x<\/mi>)<\/mo>)<\/mo>=<\/mo>k<\/mi><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>k<\/mi>x<\/mi>)<\/mo><\/mrow>\\frac{d}{dx}(\\sin(kx)) = k\\cos(kx)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
        • The Derivative of Cosine:d<\/mi>d<\/mi>x<\/mi><\/mrow><\/mfrac>(<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>k<\/mi>x<\/mi>)<\/mo>)<\/mo>=<\/mo>\u2212<\/mo>k<\/mi><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>k<\/mi>x<\/mi>)<\/mo><\/mrow>\\frac{d}{dx}(\\cos(kx)) = -k\\sin(kx)<\/annotation><\/semantics><\/math><\/li>\n<\/ul>\n\n\n\n
          \n

          Worked Example 1: Differentiating<\/p>\n\n\n\n

          Differentiate f<\/mi>(<\/mo>x<\/mi>)<\/mo>=<\/mo>4<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo>+<\/mo>3<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>f(x) = 4\\sin(2x) + 3\\cos(x)<\/annotation><\/semantics><\/math>.<\/p>\n\n\n\n
            \n
          1. Differentiate 4<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo><\/mrow>4\\sin(2x)<\/annotation><\/semantics><\/math>: The derivative of the inside (2<\/mn>x<\/mi><\/mrow>2x<\/annotation><\/semantics><\/math>) is 2. So, 2<\/mn>\u00d7<\/mo>4<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo>=<\/mo>8<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo><\/mrow>2 \\times 4\\cos(2x) = 8\\cos(2x)<\/annotation><\/semantics><\/math>.<\/li>\n\n\n\n
          2. Differentiate 3<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>3\\cos(x)<\/annotation><\/semantics><\/math>: The derivative of cos<\/mi>\u2061<\/mo><\/mspace><\/mrow>\\cos<\/annotation><\/semantics><\/math> is \u2212<\/mo>sin<\/mi>\u2061<\/mo><\/mspace><\/mrow><\/mrow>-\\sin<\/annotation><\/semantics><\/math>. So, \u2212<\/mo>3<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>-3\\sin(x)<\/annotation><\/semantics><\/math>.<\/li>\n\n\n\n
          3. Final Answer:<\/strong> f<\/mi>\u2032<\/mo><\/msup>(<\/mo>x<\/mi>)<\/mo>=<\/mo>8<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo>\u2212<\/mo>3<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>f'(x) = 8\\cos(2x) – 3\\sin(x)<\/annotation><\/semantics><\/math>.<\/li>\n<\/ol>\n<\/blockquote>\n\n\n\n
            \n\n\n\n

            5.5 Practice Problems<\/h3>\n\n\n\n

            Part A: Radians and Exact Values<\/h4>\n\n\n\n
              \n
            1. Convert 60<\/mn>\u2218<\/mo><\/msup>60^\\circ<\/annotation><\/semantics><\/math> and 225<\/mn>\u2218<\/mo><\/msup>225^\\circ<\/annotation><\/semantics><\/math> to radians (leave in terms of \u03c0<\/mi>\\pi<\/annotation><\/semantics><\/math>).<\/li>\n\n\n\n
            2. Using the unit circle, find the exact value of sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03c0<\/mi>2<\/mn><\/mfrac>)<\/mo><\/mrow>\\sin(\\frac{\\pi}{2})<\/annotation><\/semantics><\/math> and cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03c0<\/mi>)<\/mo><\/mrow>\\cos(\\pi)<\/annotation><\/semantics><\/math>.<\/li>\n<\/ol>\n\n\n\n

              Part B: Graphing Features<\/h4>\n\n\n\n
                \n
              1. For the function y<\/mi>=<\/mo>5<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>2<\/mn>x<\/mi>)<\/mo>+<\/mo>1<\/mn><\/mrow>y = 5\\sin(2x) + 1<\/annotation><\/semantics><\/math>:\n
                  \n
                • State the Amplitude.<\/li>\n\n\n\n
                • Calculate the Period.<\/li>\n\n\n\n
                • State the range of the function.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
                • Find the value of B<\/mi>B<\/annotation><\/semantics><\/math> if the function y<\/mi>=<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>B<\/mi>x<\/mi>)<\/mo><\/mrow>y = \\cos(Bx)<\/annotation><\/semantics><\/math> has a period of \u03c0<\/mi>\\pi<\/annotation><\/semantics><\/math>.<\/li>\n<\/ol>\n\n\n\n

                  Part C: Calculus<\/h4>\n\n\n\n
                    \n
                  1. Find the derivative of y<\/mi>=<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>4<\/mn>x<\/mi>)<\/mo><\/mrow>y = \\sin(4x)<\/annotation><\/semantics><\/math>.<\/li>\n\n\n\n
                  2. Find the derivative of f<\/mi>(<\/mo>x<\/mi>)<\/mo>=<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>5<\/mn>x<\/mi>)<\/mo>+<\/mo>x<\/mi>2<\/mn><\/msup><\/mrow>f(x) = \\cos(5x) + x^2<\/annotation><\/semantics><\/math>.<\/li>\n\n\n\n
                  3. Challenge:<\/strong> Find the gradient of the curve y<\/mi>=<\/mo>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>y = \\sin(x)<\/annotation><\/semantics><\/math> at the point where x<\/mi>=<\/mo>\u03c0<\/mi><\/mrow>x = \\pi<\/annotation><\/semantics><\/math>.<\/li>\n<\/ol>\n\n\n\n
                    \n\n\n\n

                    Solutions (Summary)<\/h4>\n\n\n\n
                      \n
                    • 1.<\/strong> \u03c0<\/mi>3<\/mn><\/mfrac>\\frac{\\pi}{3}<\/annotation><\/semantics><\/math>, 5<\/mn>\u03c0<\/mi><\/mrow>4<\/mn><\/mfrac>\\frac{5\\pi}{4}<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
                    • 2.<\/strong> sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03c0<\/mi>2<\/mn><\/mfrac>)<\/mo>=<\/mo>1<\/mn><\/mrow>\\sin(\\frac{\\pi}{2}) = 1<\/annotation><\/semantics><\/math>, cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03c0<\/mi>)<\/mo>=<\/mo>\u2212<\/mo>1<\/mn><\/mrow>\\cos(\\pi) = -1<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
                    • 3.<\/strong> Amp = 5<\/mn>5<\/annotation><\/semantics><\/math>; Period = 2<\/mn>\u03c0<\/mi><\/mrow>2<\/mn><\/mfrac>=<\/mo>\u03c0<\/mi><\/mrow>\\frac{2\\pi}{2} = \\pi<\/annotation><\/semantics><\/math>; Range = [<\/mo>\u2212<\/mo>4<\/mn>,<\/mo>6<\/mn>]<\/mo><\/mrow>[-4, 6]<\/annotation><\/semantics><\/math> (Center is 1, goes up\/down by 5).<\/li>\n\n\n\n
                    • 4.<\/strong> B<\/mi>=<\/mo>2<\/mn><\/mrow>B = 2<\/annotation><\/semantics><\/math> (since 2<\/mn>\u03c0<\/mi><\/mrow>2<\/mn><\/mfrac>=<\/mo>\u03c0<\/mi><\/mrow>\\frac{2\\pi}{2} = \\pi<\/annotation><\/semantics><\/math>).<\/li>\n\n\n\n
                    • 5.<\/strong> 4<\/mn><\/mspace>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>4<\/mn>x<\/mi>)<\/mo><\/mrow>4\\cos(4x)<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
                    • 6.<\/strong> \u2212<\/mo>5<\/mn><\/mspace>sin<\/mi>\u2061<\/mo><\/mrow>(<\/mo>5<\/mn>x<\/mi>)<\/mo>+<\/mo>2<\/mn>x<\/mi><\/mrow>-5\\sin(5x) + 2x<\/annotation><\/semantics><\/math><\/li>\n\n\n\n
                    • 7.<\/strong> y<\/mi>\u2032<\/mo><\/msup>=<\/mo>cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>x<\/mi>)<\/mo><\/mrow>y’ = \\cos(x)<\/annotation><\/semantics><\/math>. At x<\/mi>=<\/mo>\u03c0<\/mi><\/mrow>x = \\pi<\/annotation><\/semantics><\/math>, cos<\/mi>\u2061<\/mo><\/mrow>(<\/mo>\u03c0<\/mi>)<\/mo>=<\/mo>\u2212<\/mo>1<\/mn><\/mrow>\\cos(\\pi) = -1<\/annotation><\/semantics><\/math>. The gradient is \u2212<\/mo>1<\/mn><\/mrow>-1<\/annotation><\/semantics><\/math>.<\/li>\n<\/ul>\n\n\n\n
                      \n\n\n\n

                      <\/p>\n","protected":false},"excerpt":{"rendered":"

                      Chapter 5: Trigonometric Functions In previous years, trigonometry was about triangles. In Mathematical Methods, we transition to Circular Functions. We treat sine and cosine as waves that repeat infinitely, which allows us to model periodic phenomena like tides, sound waves, and seasonal temperature shifts. 5.1 Radian Measure Before performing calculus on trigonometric functions, we must […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[8],"tags":[],"class_list":["post-1161","post","type-post","status-publish","format-standard","hentry","category-math"],"_links":{"self":[{"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/posts\/1161","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1161"}],"version-history":[{"count":3,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/posts\/1161\/revisions"}],"predecessor-version":[{"id":1177,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=\/wp\/v2\/posts\/1161\/revisions\/1177"}],"wp:attachment":[{"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1161"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1161"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/archive4ones.com\/2ndstudy\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1161"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}